(2x+5)(2x^2-3x+1)=0

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Solution for (2x+5)(2x^2-3x+1)=0 equation: 


Simplifying
(2x + 5)(2x2 + -3x + 1) = 0

Reorder the terms:
(5 + 2x)(2x2 + -3x + 1) = 0

Reorder the terms:
(5 + 2x)(1 + -3x + 2x2) = 0

Multiply (5 + 2x) * (1 + -3x + 2x2)
(5(1 + -3x + 2x2) + 2x * (1 + -3x + 2x2)) = 0
((1 * 5 + -3x * 5 + 2x2 * 5) + 2x * (1 + -3x + 2x2)) = 0
((5 + -15x + 10x2) + 2x * (1 + -3x + 2x2)) = 0
(5 + -15x + 10x2 + (1 * 2x + -3x * 2x + 2x2 * 2x)) = 0
(5 + -15x + 10x2 + (2x + -6x2 + 4x3)) = 0

Reorder the terms:
(5 + -15x + 2x + 10x2 + -6x2 + 4x3) = 0

Combine like terms: -15x + 2x = -13x
(5 + -13x + 10x2 + -6x2 + 4x3) = 0

Combine like terms: 10x2 + -6x2 = 4x2
(5 + -13x + 4x2 + 4x3) = 0

Solving
5 + -13x + 4x2 + 4x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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